Aspirants, before attempting any competitive exam like Bank PO, Entrance Exam, SSC CGL, you should practice more on Time and Distance Questions to solve the problems easily.
Note down the tips and tricks included in the material. It can use for you while solving questions. What we learn is not enough. Hence, the candidates need to think practically as well to achieve perfection in the concept.
Now is the time to compete for the entrance and placement exams. So, candidates are suggested to prepare for the below given Time and Distance Questions and Answers.
Time and Distance - General Questions
7.5 km/hr |
8.5 km/hr |
7.2 km/hr |
10 km/hr. |
speed = (600/ 5 x 60) m/s. = 2 m/sec.
∵ apply the formula for converting m/sec. to km/h.
X m/sec = (X x 18/5) km/hr.
= (2 x 18/5) km/hr.
= 7.2 km/hr.
15 min. |
10 min. |
12 min. |
18 min. |
Due to stoppages, a bus covers 9 km less.
∵ so, Time taken to cover 9 km = (9/54 x 60) min.
= 10 min.
18 km |
20 km |
16 km |
12 km |
Let the distance travelled on foot be X km.
Then, distance travelled on bicycle = (61 - X) km.
∵ so, X/4 + (61 - X/9) = 9
⟹ 9X + 4(61 -X) = 9 x 36
⟹ 5X = 80
⟹ X = 16 km.
3 kmph |
10 kmph |
7 kmph |
5 kmph |
Let Nitin's speed be x km/hr.
∵ Then, (30/X - 30/2X) = 3
⟹ 6X = 30
⟹ X = 5 km/hr.
4 : 3 |
3 : 4 |
4 : 4 |
3 : 3 |
Let the speed of the train be X km/hr and that of the car be Y km/hr.
∵ Then, (120/X + 480/Y) = 8
⟹ 1/X + 4/Y = 1/15 ...(ⅰ)
and, (200/X + 400/Y) = 25/3
⟹ 1/X + 2/Y = 1/24 ...(ⅱ)
Solving (i) and (ii), we get: X = 60 and Y = 80.
∵ Ratio of speeds = 60 : 80 = 3 : 4.
1 2 3 ≫
0 Comments