Time and Distance - General Questions
600 kmph |
750 kmph |
720 kmph |
850 kmph |
Distance = (240 x 5) = 1200 km
Speed = Distance/Time
Speed = 1200/(5/3) km/hr. [We can write 1(2/3) hours as 5/3 hours]
∵ Required speed = (1200 x 3/5) km/hr. = 720 km/hr.
3 hour |
5 hour |
7 hour |
1 hour |
Let the duration of the flight be X hours.
Then, 600/X - 600/X + (1/2) = 200
⟹ 600/x - 1200/2X + 1 = 200
⟹ X(2X + 1) = 3
⟹ (2X + 3)(X - 1) = 0
∵ X = 1 hr.
57 km/hr |
87.5 km/hr |
42 km/hr |
80 km/hr |
Let the speed of two trains be 7X and 8X km/hr.
Then, 8X = 400/4 = 100
⟹ X = 100/8 = 12.5
∵ Speed of first train = (7 x 12.5) km/hr = 87.5 km/hr.
71.11 km/hr |
75 km/hr |
65 km/hr |
60 km/hr |
Total time taken = (160/64 + 160/80) hrs. = 9/2 hrs.
∵ Average speed = (320 x 2/9)km/hr = 71.11 km/hr.
20 kmph |
15 kmph |
12 kmph |
10 kmph |
Let the distance travelled by X km.
Then, X/10 - X/15 = 2
⟹ 3X - 2X = 60
⟹ X = 60 km
Time taken to travel 60 km at 10 km/hr = (60/10)hrs = 6 hrs.
So, Sachin started 6 hours before 2 P.M. i.e., at 8 A.M.
∵ Required speed = (60/5)hrs. = 12 km/hr.
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