Aspirants, before attempting any competitive exam like Bank PO, Entrance Exam, SSC CGL, you should practice more on Time and Problems on Trains to solve the problems easily.
Note down the tips and tricks included in the material. It can use for you while solving questions. What we learn is not enough. Hence, the candidates need to think practically as well to achieve perfection in the concept.
Now is the time to compete for the entrance and placement exams. So, candidates are suggested to prepare for the below given Problems on Trains Questions and Answers.
Problems on Trains - General Questions
160 metres |
155 metres |
150 metres |
152 metres |
speed = (60 x 5/18) m/s. = (50/3) m/s.
Length of the train = (Speed x Time).
∵ Length of the train = (50/3 x 9) m.
= 150 m.
36 sec. |
48 sec. |
49 sec. |
45 sec. |
Relative speed = (60+ 90) km/hr
= (100 x 5/18) m/sec.
= (125/3) m/sec.
∵ Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
∵ Required time = (2000 x 3/125) sec. = 48 sec.
18 sec |
3.6 sec |
36 sec |
72 sec |
Speed of train relative to jogger = (45 - 9) km/hr = 36 km/hr.
= (36 x 5/18) m/sec
= 10 m/sec.
∵ Distance to be covered = (240 + 120) m = 360 m.
⟹ Time taken = (360/10) sec = 36 sec.
45 sec |
48 sec |
42 sec |
40 sec |
apply the formula for converting km/hr to m/s : (X x 5/18) m/s.
Therefore, Speed = (45 x 5/18) m/s. = 25/2 m/s.
∵ Total distance to be covered = (360 + 140) m = 500 m.
formula for finding time = Distance/speed
∵ Then, Required time = (500 x 2/25) sec. = 40 sec.
160 m |
175 m |
150 m |
155 m |
Length of the train is equal to the distance covered by train to cross the pole. So, applying the following formula:
∵ Distance = Speed x Time
Speed is given in Km/hr therefore we will convert it into m/s as answers are given in meters.
⟹ Speed = 90 x 5/18 = 25 m/s
⟹ Time = 7 seconds
⟹ Distance = 25 x 7 = 175 meters
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