Are you weak in Problems on Trains concept? If so, then this article is for you. Below we have provided Problems on Trains Quiz. Wherein, we provide you the best way to solve problems even in critical situations.

Aspirants, before attempting any competitive exam like Bank PO, Entrance Exam, SSC CGL, you should practice more on Time and Problems on Trains to solve the problems easily.

Note down the tips and tricks included in the material. It can use for you while solving questions. What we learn is not enough. Hence, the candidates need to think practically as well to achieve perfection in the concept.

Now is the time to compete for the entrance and placement exams. So, candidates are suggested to prepare for the below given Problems on Trains Questions and Answers.

Aptitude :: Problems on Trains

Practice :: Problems on Trains - General Questions
Problems on Trains - General Questions

Page Title 1. A train crosses a pole in 9 seconds with a speed of 60 km/h. Then what is the length of the train?
160 metres
155 metres
150 metres
152 metres
Answer: option C

speed = (60 x 5/18) m/s. = (50/3) m/s.

Length of the train = (Speed x Time).

∵ Length of the train = (50/3 x 9) m.

= 150 m.



2. Two trains are running in opposite directions with speeds of 60 km/h and 90 km/h respectively. They have a length of 1.10 km and 0.9 km respectively. In how much time can the slower train cross the faster train?
36 sec.
48 sec.
49 sec.
45 sec.
Answer: option B

Relative speed = (60+ 90) km/hr

= (100 x 5/18) m/sec.

= (125/3) m/sec.

∵ Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.

∵ Required time = (2000 x 3/125) sec. = 48 sec.



3. A jogger running at a speed of 9 kmph along a railway track in 240 m in front of the engine of a 120 m long train moving at 45 kmph in the same direction. In what time will the train cross the jogger?
18 sec
3.6 sec
36 sec
72 sec
Answer: option C

Speed of train relative to jogger = (45 - 9) km/hr = 36 km/hr.

= (36 x 5/18) m/sec

= 10 m/sec.

∵ Distance to be covered = (240 + 120) m = 360 m.

⟹ Time taken = (360/10) sec = 36 sec.



4. A train is running at a speed of 45 km/h and its length is 360 m. In what time will it cross the 140 m long bridge?
45 sec
48 sec
42 sec
40 sec
Answer: option D

apply the formula for converting km/hr to m/s : (X x 5/18) m/s.

Therefore, Speed = (45 x 5/18) m/s. = 25/2 m/s.

∵ Total distance to be covered = (360 + 140) m = 500 m.

formula for finding time = Distance/speed

∵ Then, Required time = (500 x 2/25) sec. = 40 sec.



5. At a speed of 90 km/h a train is running and crosses a pole in 7 seconds. Find the length of the train.
160 m
175 m
150 m
155 m
Answer: option B

Length of the train is equal to the distance covered by train to cross the pole. So, applying the following formula:

∵ Distance = Speed x Time

Speed is given in Km/hr therefore we will convert it into m/s as answers are given in meters.

⟹ Speed = 90 x 5/18 = 25 m/s

⟹ Time = 7 seconds

⟹ Distance = 25 x 7 = 175 meters




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